As shown in figure pulley is ideal and strings are massless. If mass m of hanging block is the minimum mass to set the equilibrium of system then – (g = 10 m/s 2 )
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(a, c)
for 20 kg block
20 × 10 × 
= 0.5 × 20 × 10 × 
+ T
120 = 80 + T
T = 40 N
2 mg cos 37 0 = T
2m × 10 × 
= 40
m = 2.5 kg
force applied by 20 kg block on inclined = 
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